Daniel B. answered 12/11/20
A retired computer professional to teach math, physics
Using the identity
a³ - b³ = (a - b)(a² + ab + b²)
we can rewrite
f(x) = x³ - 3³ = (x - 3)(x2 + 3x + 9)
Therefore besides the real root 3, f(x) has the roots of
x² + 3x + 9 = 0
whose roots are of the form
x = (-3 +- sqrt(9 - 36))/2
So the two complex root are
x1 = (3/2)(-1 + i sqrt(3))
x2 = (3/2)(-1 - i sqrt(3))
Chloe B.
Thank you so much!12/14/20