Jon P. answered 02/16/15
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120 years is 4 times the half life.
So the amount of cobalt-60 remaining after 120 years is (1/2)4 of the original amount, which is 1/16.
So the amount of radioactivity from the cobalt-60 would go to 1/16 of the original. 1/16 of 100 is 6.25 mCi.