P(at least 1 green) = 1 - P(no green)
P(no green) = draw yellow on both draws = P(draw yellow on 1st draw) * P( draw yellow on 2nd draw, given draw yellow on 1st draw) = 5/9 * 4/8 = 20/72 = 5/18
P(at least 1 green) = 1 - 5/18 = 13/18
Hailey L.
asked 10/04/20P(At least 1 green) =
P(at least 1 green) = 1 - P(no green)
P(no green) = draw yellow on both draws = P(draw yellow on 1st draw) * P( draw yellow on 2nd draw, given draw yellow on 1st draw) = 5/9 * 4/8 = 20/72 = 5/18
P(at least 1 green) = 1 - 5/18 = 13/18
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