What is the concentration of K+ in mg/L (ppm) for a solution that is 0.00447 M of K2SO4? Do NOT use scientific notation in your answer.

Answer 1

0.00447 M of K2SO4 = 0.00447 moles/ L

Now we use dimensional analysis:

0.00447 moles x 2 mole. K⁺ x 39.1 gram x 1000mg = 367.54 mg/L

L 1 mole K2SO4 1 mol K^+. 1 gram