Take log base 5 of both sides to get:
log5(53x − 1) = log5(6) then use the property of logs that brings an exponent out front to get:
(3x - 1)log5(5) = log5(6)
(3x - 1)(1) = log5(6)
3x = log5(6) + 1
x = (log5(6) + 1)/3
Viviana C.
asked 10/03/20Consider the following.
53x − 1 = 6
(a) Find the exact solution of the exponential equation in terms of logarithms.
x =
Take log base 5 of both sides to get:
log5(53x − 1) = log5(6) then use the property of logs that brings an exponent out front to get:
(3x - 1)log5(5) = log5(6)
(3x - 1)(1) = log5(6)
3x = log5(6) + 1
x = (log5(6) + 1)/3
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