Specific Heat Capacity

Question

The specific heat capacity of lead is 0.13 J/g ^oC. How much heat (in J) is required to raise the temperature of 15.8 g of lead from 25.6°C to 35.1°C? Keep three significant figures in your answer. 

Answer 1

The specific heat capacity tells us how much energy is stored in a certain amount of a compound at a temperature.

The equation for heat (q) is: q=specific heat (s) * mass (m) *DeltaT(Tf-Ti)

Delta T will always be Tfinal - Tinitial

in this case q=0.13J/(g*C)*(15.8 g of lead)*(35.1C-25.6C)= 19.5 J note that the units cancel out.