David H. answered • 09/30/20
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nKOH=(140ml x 0,69M) : 1000 = 0,0966 mol
nH2SO4= 0,0966mol : 2 = 0,0483 mol
VH2SO4= (0,0483 mol : 0,4 M ) x 1000 = 120,75 (ml)
Lu J.
asked • 09/30/20Given balanced equation between H2SO4(aq) and KOH(aq)
H2SO4(aq)+2KOH(aq)----->K2SO4(aq)+2H2O(l)
What volume (in mL) of 0.4M H2SO4(aq)soluton is necassary to complete with 140 ml of 0.69M KOH(aq)
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Lu J.
thank you!10/01/20