What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (−2, 4)? y = – Five-halvesx – 1 y = – Five-halvesx + 5 y = Two-fifthsx – 1 y = Two-fifthsx + 5

Answer 1

5x+2y = 12

2y =-5x +12

y = (-5/2)x + 6

the slope = -5/2 = also the slope of any parallel line

use the point slope formula to find that parallel line through (-2,4)

y-4 = (-5/2)(x+2)

multiply by 2

to eliminate the fraction, to get

2y-8 =-5x-10

5x+2y =-2 is the equation of the line that is parallel to 5x+2y=12 and passes through the point (-2,4)