A sample of nitrogen occupies 1.00 L at a temperature of 250. K. What volume would it occupy at 1500. K?

Answer 1

Assuming the pressure remains constant we can use Charles' Law ... V1/T1 = V2/T2

V1 = initial volume = 1.00 L

T1 = initial temperature = 250 K

V2 = final volume = ?

T2 = final temperature = 1500 K

1.00 L/250K = V2/1500K

V2 = 6.00 L

(Note that the temperature increased so to keep the pressure the same, the volume must also increase)