What is the mass of hydrogen and oxygen needed to make 29 grams of hydrogen peroxide?

Answer 1

Given: 29g H₂O₂

Find mass of H and O

Reaction: H₂ + O₂ == H₂O₂

From Perodic Table: H = 1.008 amu, O = 15.999 amu (atomic mass unit)

H₂O₂ = 34.014 amu

H Equation: 29g H₂O₂ X 1 H₂O₂ mol/34.014g X 1.008gH/mol H X 2 mol H/mol H₂O₂ = 1.719g H

O: 29g - 1.719g = 27.28g O

Round to 2 significant digits: 1.7g H and 27.3g O