For the chemical reaction CaI2+2AgNO3⟶2AgI+Ca(NO3)2 how many moles of silver iodide (AgI) are produced from 8.0 mol of calcium iodide (CaI2)?

Answer 1

Hello Guys!

So this is a basic stoichiometry problem. We know that the there is a 2:1 ratio between AgI and CaI₂. Therefore, if we have 8.0 moles of CaI₂ we will generate, theoretically, 16.0 moles of AgI.