Since f-1(2) = 3, f(3) = 2 and since f-1(-3) = 6, f(6) = -3.
So, f(3) = 3a + b = 2 and f(6) = 6a + b = -3.
3a + b = 2
6a + b = -3
Subtract the equations to get -3a = 5.
Therefore, a = -5/3 and b = 7.
So, f(x) = (-5/3)x + 7.
David E.
asked 09/24/20Find the parameters a and b included in the linear function f(x) = a x + b so that f -1 (2) = 3 and f -1 (-3) = 6, where f -1 (x) is the inverse of function f.
Since f-1(2) = 3, f(3) = 2 and since f-1(-3) = 6, f(6) = -3.
So, f(3) = 3a + b = 2 and f(6) = 6a + b = -3.
3a + b = 2
6a + b = -3
Subtract the equations to get -3a = 5.
Therefore, a = -5/3 and b = 7.
So, f(x) = (-5/3)x + 7.
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