an ice skater starts with a velocity of 2.25 m/s in a 50 degree direction. after 8.33 s, she is moving 4.65 m/s in a 120 degree direction. what is the y-component of her acceleration

Answer 1

V_{y initial}=(2.25 m/s)sin50⁰ = 1.72 m/s

V_{y final}=(4.65 m/s)sin(180-120)⁰= 4.03 m/s

a_y= (V_{y final} -V_{y initial})/t=(4.03 -1.72)/8.33=0.277 m/s^2≈0.28 m/s²