When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 40.6 g KCl, how many grams of O2 were produced?

Answer 1

From the balanced equation, we see that molar ratio of O₂ to KCl is 3:2. Therefore,

(32.0 g O₂ g/1 mol O₂) (3 mol O₂/2 mol KCl) (1 mol KCl/74.5 g KCl) (40.6 g KCl) = 26.2 g O₂