Hello, Daisy,
We need the specific heat of the transition of state of water (fusion) for this calculation. Your book should have a table for this value. I'll use 334 J/g, which I believe is the accepted value. This number simply means that 334J of energy is required to melt 1g of ice. Note that the temperature remains at 0o C. We are melting the ice, but not warming it above 0 C.
We have 5.00 kg of ice. Multiply the specific heat of water fusion by the mass:
334 J/g * (5.00 kg) = [Note that the unit is per gram, but we have the mass in kg].
Let's convert the 5.00 kg into grams. 1000 g = 1,00 kg, so 1 = 1000g/kg
Now we can do the calculation: 334 J/g * (5.00 kg) * (1000 g/kg) = 1.67 x 106 Joules.
This could also be expressed in kJ as 1670 kJ
Bob