CuSO4 5H2O Chemistry Homework Question

Question

How many mL of 0.40 M CuSO4 5H20 are needed to make 10.0 mL of 0.080 M CuSO4?

Answer 1

Hi there!

Recall that M for molarity is defined as moles per liter, mol / L. This is a problem where we are diluting a chemical solution by adding some amount of water.

Since our amount of CuSO4 (moles of the stuff) isn't changing, the equation we need is

M1V1 = M2V2 ; where M is molarity (mol / L) and V is volume (L)

Solving for V1, as that is our goal, we find that:

V1 = M2V2 / M1

Substituting our values in and being careful about mL vs. L (factor of 1000), we find:

V1 = 0.080 M * 0.010 L / 0.40 M = 0.002 L = 2.0 mL (2 sig figs following sig fig rules)

I'm assuming the 5H2O either remains part of the compound in the second solution.

Hope this helps, and let me know if you have any further questions!