PLEASE HELP NOW, I AM STRESSING AND I AM HORRIBLE AT MATH!!! PLEASE!!!

Question

A cruise ship travels at a bearing of N35°E at 18 mph for 3 hours and changes course to a bearing of S66°E. It then travels 15 mph for 2 hours. Find the distance the ship is from its original position

Answer 1

18x3 = 54 miles 35 degrees east of north

then 15x2 = 30 miles at 66 degrees east of south

difference in the angles is 90-35 +90-66 = 55 +24 = 79 degrees

the angle between 54 and 30 is 180-79= 101

construct a right triangle SAS, Side Angle Side, 54 miles, 101 degrees 30 miles

to find the 3rd side of the triangle, opposite 101 degrees, use the Law of Cosines

c^2 = a^2 + b^2 -2abCosC

c^2 = 54^2 + 30^2 - 2(54(30)Cos101

= 2916+ 900 - 3240(-Cos79)

= 3916 + 618.22

= 4534.22

c = square root of 4534.22

c= about 67.34 miles from its origiinal position

It definitely helps to draw a diagram. It's not an easy problem

It should have been listed under the category "Trigonometry"