How many grams of NH3 can be made from 4.85 mol of H2 and excess N2?

Answer 1

Hello, Rebecca,

First, balance the equation:

3H2 + 1N2 = 2NH3

That gives us 6 H and 2 N on both sides.

Next, calculate the molar mass of each component:

Units are in g/mole H2 N2 NH3

2 28 17

There is an excess of N2, so the reaction is limited by the 4.85 moles of H2. The balanced equation tells us that it takes 3 moles of H2 to produce 2 moles of NH3.

Therefore, if we convert all of the H2, we would get:

4.85 mol H2 * (2 moles NH3/3 moles H2) = 3.23 moles of NH3

The mass of NH3 is thus: 3.23 moles NH3 * (17g/mole) = 55 grams NH3

I hope this helps,

Bob