Express your answer to four significant figures.

Question

Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the piping. However, consider a pipe where water was allowed to sit in the pipe. The hot water cools as it sits in the pipe. What is the temprature change, (ΔT), of the water if 201.5 g of water sat in the copper pipe from part A, releasing 2122 J of energy to the pipe? The specific heat of water is 4.184 J/(g⋅∘C).

Answer 1

Hello Anya, you need to determine the temp change in water when hot water sits in copper pipes.

The formula you will use

Q = m c deltaT, where Q = quantity of heat released or absorbed, m = amt of substance(water), c = specific heat of water and deltaT = change in temp.

Q = 2122 joules

m=201.4 g

c = 4.184j/g degree C

Substitute these values and solve for change in temp.

2122 j = 201.5g * 4.184j/g degree C * delta T

Delta T = 2122/201.5 g * 4.184 = 2.517 degree C which is your ans in four sig figure.