please complete this code :(same variables )

Question

hi this is my code to multiple two large numbers can you please complete it so it divides two numbers too (without changing the variables in the code and please be sure it compile correctly with this variables) :

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

int main()

{

int a[200],b[200];

int answer[200]={0};

int i,j,tmp;

char s[100],d[100];

puts("please enter 2 numbers :");

scanf(" %s",s);

scanf(" %s",d);

int l1 = strlen(s);

int l2 = strlen(d);

for(i = l1-1,j=0;i>=0;i--,j++)

{

a[j] = s[i]-'0';

}

for(i = l2-1,j=0;i>=0;i--,j++)

{

b[j] = d[i]-'0';

}

for(i = 0;i < l2;i++)

{

for(j = 0;j < l1;j++)

{

answer[i+j] += b[i]*a[j];

}

}

for(i = 0;i < l1+l2;i++)

{

tmp = answer[i]/10;

answer[i] = answer[i]%10;

answer[i+1] = answer[i+1] + tmp;

}

for(i = l1+l2; i>= 0;i--)

{

if(answer[i] > 0)

break;

}

printf("result : ");

for( ;i >= 0;i--)

{

printf("%d",answer[i]);

}

return 0;

}

Answer 1

You were given an algorithm to solve this problem.

You need to take the algorithm given and write the code yourself.

Once again, check MULTIPLES of the divisor until you get a product that is GREATER

than the dividend. Then subtract to find the remainder.

Here is another example.

EX. 1000 divided by 111

The DIVISOR is 111; the dividend is 1000

111*1 = 111

111*2 = 222

111*3 = 333

111*4 = 444

111*5 = 555

111*6 = 666

111*7 = 777

111*8 = 888

111*9 = 999

111*10 = 1110 <-- too big; backs up one

the quotient is 9, the partial product is 999 and the remainder is 1000-999=1

figure it out