
William W. answered 08/29/20
Math and science made easy - learn from a retired engineer
Density is mass/volume (D = M/V) and, in this case, we are trying to find the density of the unknown solid so:
Density(unknown solid) = (mass(unknown solid))(volume(unknown solid))
The mass of the unknown solid is the mass of the clean pycnometer plus metal sample (40.505g) - mass of clean pycnometer (25.151g) = 40.505 - 25.151 = 15.354 g
Now we need to volume of the unknown solid. It happens that the volume of the unknown solid is the same as the volume of the ejected water. To find this, we need to use the equation D = M/V which we can change to V = M/D by multiplying both sides by V and then dividing both sides by D. We are given that the density of water is 1.000 g/cm3 so all we need is the mass of the ejected water.
We are given that the mass of the clean pycnometer plus water = 42.481g and we already calculated the mass of the unknown solid so the combination is 42.481 + 15.354 = 57.835 g
We are given that the mass after the water is ejected is 54.265 g so the mass of the ejected water must be 57.835 - 54.265 = 3.57g. Using V = M/D we can calculate the volume of the ejected water to be 3.57/1.000 = 3.57 cm3, which, again, is also the volume of the unknown solid.
So, the final calculation is D = mass/volume = 15.354/3.57 = 4.301 g/cm3 (we use 4 significant figures because we are given the density of water with 4 significant figures)