In this question, we need to be aware of relevant information that presents components to help us solve for a variable.
Given: 0.419M glucose means the concentration of glucose. Concentration is moles of solute/ liters of solution.
1st step: Convert 465.8 mL to L
(465.8 mL) (10-3L/1mL) = 0.4658 L
2nd step: Plug information into concentration formula as mentioned above:
0.419 M = (x moles of glucose)/0.4658 L
x moles of glucose = 0.419 M x 0.4658 = 0.195 moles of glucose in 3 significant figures.
3rd step: Convert moles to grams of glucose. To do this, we need to calculate the molar mass of glucose and then multiply by number of moles that we just calculated. Molar mass of glucose is 180 g/mol since there are 6 carbons, 12 hydrogens, and 6 oxygens. Multiply each quantity with its respective atomic mass. (6 x12) + (1 x 12) + (6x16) = 180 g/mol
0.195 moles of glucose x 180 g/mol = 35.1 g of glucose
