Scott D. answered 10/21/20
Knowledgeable Astronomy Tutor with 3 Years Teaching Experience
The period is 240 million years. There are 60 x 60 x 24 x 365.25 sec in a year = 31557600 seconds. So the period of the orbit is 7.5738 x 1015 sec or 2.1038 x 1012 hours. A light year is (31557600 sec)(3 x 108 m/sec) = 9.4673 x 1015 m. Because there are 1000 m in one km, a light year is 9.4673 x 1012 km. Therefore the radius of the planet's orbit is (28000 ly)(9.4673 x 1012 km/ly) = 2.6508 x 1017 km. Circumference = 2πr so the circumference of the orbit is 2π(2.6508 x 1017 km) = 1.6655 x 1018 km. Since the planet travels this circumference in the period, its average speed is
(1.6655 x 1018 km) / (2.1038 x 1012 hours) = 7.917 x 105 km/hr