double indicator titration

Question

A solution contains both NaHCO₃ and Na₂CO₃. Titration of a 50.00 mL portion to a phenolphthalein end point requires 21.98 mL of 0.1113 M HCl. A second 50.00 mL aliquot requires 46.96 mL of the HCl solution when titrated to a bromocresol green end point. Calculate the molar concentration of NaHCO₃ in the solution. (Do not include the unit for molarity. Enter your answer to three significant figures.)

Answer 1

Hey Akshay, here's my answer and explanation to your question: https://youtu.be/QrBSDiUysHk

Cheers,

Answer 2

The first titration endpoint indicates the moles of Na₂C0₃ that are converted to NaHCO₃ which is .00244637.

The second will give both NaHCO₃ and Na₂CO₃. converted to H₂CO3 which is .00555721, so the difference will be the moles of NaHCO_{3 in the original solution. using the original volume of .050 L the answer is : 0.0622 M}