1) One approach, which I will use here, is to find the volume of CO2 that would be produced at STP, then convert this, using the combined gas law, to the given conditions.
Li2O + CO2 → Li2CO3
(22.4 L CO2/1 mol CO2) (1 mol CO2/1 mol Li2CO3) (1 mol Li2CO3/30.0 g Li2CO3) 1000 g Li2CO3 = 747 L CO2
PSVS/TS = P2V2/T2
V2 = [(1.013 x 105Pa) (747 L) (298.15 K) (1 hPa)]/[(1010 hPa) (100 hPa) (273.15 K)] = 817 L
2) This is somewhat the reverse of the previous question. Here, the best approach is to use the CGL to convert the given volume at the given conditions to STP, then use stoichiometry to get the mass of HgO
Vs = P1V1Ts/PsT1
= [(1025 hPa) (100 Pa) (0.025L) (273.15 K)]/[(1 hPa) (1.013 x 105Pa)(308.15 K)] = 0.0224 L
(217 g HgO/ 1 mol HgO) (2 mol HgO/1 mol O2) (1 mol O2/22.4 L) 0.0224 L = 0.434 g HgO

John M.
08/21/20
George P.
I understand it now thank u08/21/20