The reaction between sodium metal and water produces sodium hydroxide and hydrogen gas. If 35.0g of each sodium metal and water are initially reacted, calculate the mass of sodium hydroxide produced.

Answer 1

2 Na + 2 H2O → 2 NaOH + H₂

(40.0 g NaOH/1 mol NaOH) ( 2 mol NaOH/2 mol Na) (1 mol Na/23.0 g Na) 35.0 g Na = 60.9 g NaOH