There are 6.02 x 10^23 molecules in 1 mol of S2F10
numbers of mol present in 7.19×1022 molecules = 7.19×1022 / 6.02 x 10^23 =0,019 molecules
Nick P.
asked 07/30/20There are 6.02 x 10^23 molecules in 1 mol of S2F10
numbers of mol present in 7.19×1022 molecules = 7.19×1022 / 6.02 x 10^23 =0,019 molecules
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