There are 6.02 x 10^23 molecules in 1 mol of S2F10, but in 1.58 mol =
=6.02 x 10^23 x 1.58 = 9,51 x 10^23 molecules
Nick P.
asked • 07/30/20How many MOLECULES of disulfur decafluoride are present in 1.58 moles of this compound ?
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