How many GRAMS of chlorine are present in 4.22×1022 molecules of phosphorus pentachloride ?

Answer 1

One mole of molecules, which is known to be 6.02 x 10^23 (Avogadro's number)

Let's find how many mol we have.

4.22 x 10^22 / 6.02 x 10^23 =0.07 mol

Molar mass of Cl5P= 208.5g where 177.5 g of Chlorine is present

so, mass of Chlorine in 0.07 mol of Cl5P= 177.5 x 0.07= 12,43 gram