David T.
asked • 07/27/20What are the odds?
In a group of 6 people, what are the odds that 3 of them have the same yearly birthday (month and year)?
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1 Expert Answer
Patrick B. answered • 07/27/20
Tutor
4.7
(31)
Math and computer tutor/teacher
counting the leap day of feb 29, the probability is 1/366*1/365* 1/364*1/363*1/362
= 1/6,389,848,024,560
So the odds are 1 to 6389848024561 in favor and 6389848024560 to 6389848024561 against
Jeffrey K.
This isn't quite correct. We need to take into account the number of ways the 3 can be chosen from the 6 = 6C3 where C means combinations = 6! / 3! 3! = (6 x 5 x 4) / (3 x 2 x 1) = 20 So, the answer is 20 times the number given above (which is still very small!)
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07/27/20
David T.
So, it would be 1/127,796,960,491,200 ??
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07/28/20
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Stanton D.
Yearly birthday is not month and year. What did you mean, really?07/27/20