Write the equation of the line that passes through point (6, 2) with slope 2/3 in point-slope form and in slope-intercept form.

Answer 1

Slope intercept form is y=mx + b. In this equation, m is the slope and b is the y-intercept. Point slope form is y-y₁= m(x-x₁). In this equation, m is again the slope and x₁,y₁ is where you plug in points from the line.

To solve this problem, plug in the given point to both forms of the equation to solve for the unknowns:

2 = (2/3)*(6)+b

2 = 4+b

b= -2

so slope intercept form is y = (2/3)x -2

To find the point slope form, simply plug in m and the point given.

y-2 = (2/3)*(x-6)

Just a note, you can see that these two equations will give the same value if you solve the point slope form for y.