CaI2(aq) + 2NaOH(aq) Ca(OH)2(s) + 2NaI(aq)

Question

Calculate the number of milliliters of 0.442 M NaOH required to precipitate all of the Ca²⁺ ions in 130 mL of 0.677 M CaI₂ solution as Ca(OH)₂. The equation for the reaction is

?  mL NaOH

:

Answer 1

Step 1- Use the Molarity equation (M=moles/Liter) to find the number of moles of CaI₂ present

Step 2- Use the stoichiometry of the equation CaI₂ -> Ca⁺² + 2 I^- to find the number of moles of Ca⁺²

Step 3- Use the stoichiometry of the equation Ca⁺² + 2 OH^- -> Ca(OH)₂ to find the number of moles of OH^- needed

Step 4- Use the stoichiometry of the equation Na⁺ + OH^- -> NaOH to find the moles of NaOH needed

Step 5- Use the molarity equation to find the number of Liters of NaOH solution needed and then convert that to milliliters