The increase in Kinetic Energy is (0.5)(1500)(15)^2 = 168.750 J
This happened over 6 seconds so Power =Work/Time = 168750/6 = 28,125 Watts
Aya K.
asked • 07/22/20A 1.5 × 103 kg vehicle on a level road accelerates from rest to 15.0 m/s in 6.00 s. Determine the output of power in the car in this 6.00 s. Ignore friction.
A 1.5 × 103 kg vehicle on a level road accelerates from rest to 15.0 m/s in 6.00 s. Determine the output of power in the car in this 6.00 s. Ignore friction.
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