M = moles of solute/L of solution.
Cr2(SO4)3 = 392 g/mol
(1 mol/392 g) (19.2 g/0.375 L) = 0.131 m/L = 0.131 M
Alexandria P.
asked 07/21/20What is the molarity of the solution? M
M = moles of solute/L of solution.
Cr2(SO4)3 = 392 g/mol
(1 mol/392 g) (19.2 g/0.375 L) = 0.131 m/L = 0.131 M
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