What volume of a 0.307 M nitric acid solution is required to neutralize 21.1 mL of a 0.110 M potassium hydroxide solution?

Question

 mL nitric acid

Answer 1

Utilize the titration formula of M₁V₁= M₂V₂ since we are given the concentrations of each compound and the volume of KOH.

Let: M₁= 0.307 M, V₁= x, M₂ = 0.110 M, V₂= 21.1 mL

M₁V₁= M₂V₂

(0.307) (V₁) = (0.110)(21.1)

V₁= (0.110 x 21.1)/ (0.307)

V₁ = 7.56 mL