Evaluate the function at each specified value of the independent variable and simplify.

Question

f(t) = 3t + 1

(a) f(2) (B) f(-4) (C) f( t + 2 )

Answer 1

These used to confuse me, too. We simply take what is given inside the parentheses and substitute it for t.

f(2) = 3(2) + 1 = 6 + 1 = 7

f(-4) = 3(-4) + 1 = -12 + 1 = -11

f(t + 2) = 3(t + 2) + 1 = 3t + 6 + 1 = 3t + 7