Tom K. answered 07/08/20
Knowledgeable and Friendly Math and Statistics Tutor
This, while an algebra problem, is a formula you usually see at the beginning of calculus classes; as h goes to 0, the formula approaches the slope of the function at x (also known as the first derivative). Note that, while the denominator is written as h, it could be written as x + h - h, which tells us that the formula is the slope of a line from (x, f(x) ) to (x+h, f(x+h))
f(x+h) = 5 * (x+h)^2 + 4 = 5(x^2 + 2hx + h^2) + 4 = 5x^2 + 10hx + 5h^2 + 4
f(x) = 5x^2 + 4
Thus, f(x+h) - f(x) = 5x^2 + 10hx + 5h^2 + 4 - (5x^2 + 4) = 10hx + 5h^2, and
(f(x+h)-f(x))/h = (10hx + 5h^2)/h = 10x + 5h
As h goes to 0, this goes to 10x, which tells us that the slope of the function at x is 10x.