Ishwar S. answered • 07/05/20
University Professor - General and Organic Chemistry
5,6,7- triethyl-4-methyl-2-nonene
H3CCHCHCH(CH3)CH(CH2CH3)CH(CH2CH3)CH(CH2CH3)CH2CH3
The C=C in the above structure is on C2 on the left (H3CCHCH....) and the numbering of the substituents continues to the right. Methyl is on C4 and the three ethyl groups are on C5, C6 and C7, respectively. I am redrawing the structure below so that you can see the bond connectivity.
H3C–CH=CH–CH(CH3)–CH(CH2CH3)–CH(CH2CH3)–CH(CH2CH3)–CH2–CH3
3-methyl-4,4-dipropyl-1-octyne
HCCCH(CH3)C(CH2CH2CH3)2CH2CH2CH2CH3
The C≡C in the above structure is on the left (HC≡C....) and the numbering of the substituents continues to the right. Methyl is on C3 and the two propyl groups are on C4. I am redrawing the structure below so that you can see the bond connectivity.
HC≡C–CH(CH3)–C(CH2CH2CH3)2–CH2–CH2–CH2–CH3
Ishwar S.
Okay, thank you. I updated the first structure to make it 2-nonene.07/06/20
Jenny F.
Hello. No I meant 2-nonene07/05/20