JH K.

asked • 06/30/20

I have a physics question.

I have a massless and frictionless string attached to 2 balls on each end. The 2 balls may have different masses. There is also a pivot in the middle of the string, such that the string can slide on the pivot freely. At first, the balls are at rest and horizontal to the pivot. How can I calculate the tension in the string when the 2 balls are dropped, given the masses of the balls and the length of the string?

1 Expert Answer

By:

JH K.

Hi, thank you for responding. However, doesn't the tension not always act opposite to gravitational force, as the string is at an angle to the horizontal, so the acceleration is not only upward?
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06/30/20

John B.

tutor
The question potentially has multiple components which are not specified. During the time when the balls are falling from the horizontal there will be a time and angle dependent tension in each string. I was assuming the tension after they have fallen to the vertical position.
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06/30/20

JH K.

Sorry, I did not phrase my question very clearly. My question was to express the tension in terms of the angles between the strings and the vertical, or preferably, in terms of time, when the balls are falling. I would also like to clarify that, if the balls are of different masses, wouldn't they not come to equilibrium at all, and keep moving until the lighter ball is at the pivot?
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07/01/20

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