A perfect cube of a gold metal was found to have a mass of 45.85 g. The density of the gold is 19.3 g/cm3 . Calculate the dimensions of the cube

Answer 1

Start with an equation:

Density = mass / volume

Substitute in what you know:

19.3 g/cm³ = 45.85 g/ V

Solve for volume:

V = 45.85 g / 19.3 g/cm³ = 2.38 cm³

Now to find the dimensions:

V = 3√l

Again substitute:

2.38 cm³ = 3√l

Isolate l by cubing both sides.

l = (2.38 cm³)³ = 13.5 cm

The dimensions of the cube are 13.5 cm.