Arthur D. answered 06/15/20
Mathematics Tutor With a Master's Degree In Mathematics
Here's the rectangular form if this helps:
r=2cosθ is the given equation
x=rcosθ
y=rsinθ
multiply both sides of equation 1 by r
r^2=2rcosθ
but rcosθ=x
substitute
r^2=2x
now r^2=x^2+y^2
substitute
x^2+y^2=2x
x^2-2x+y^2=0
complete the square
x^2-2x+1+y^2=1
(x-1)^2+y^2=1