It should have one solution = .652919
if e-x2 = x, then -x2ln(e) = ln(x) or -x2 = ln(x) or x2 + ln(x) = 0
Looking at the graph and seeing that it crosses the x axis only once, the result is given using methods such as Newton's method.

Mark J.
06/15/20
Kojo K.
Intermediate Value Theorem06/15/20

Mark J.
06/15/20
Kojo K.
Yes please. THank you so much06/15/20

Mark J.
06/15/20
Kojo K.
Thank you. How can you use IVT to show that the function has at least one root between [0,1]?06/15/20