strength and dynamic

Question

The yield strength of the steel key and shaft is σY= 400 MPa. 32.5 Nm torque is applied to shaft. Determine if the loadings cause the key to fail ?

(Diameter of shaft=10 mm, height of the key=5 mm, width of the key=3 mm, length of the key= 36 mm)

Answer 1

The simplified standard calculation for key/keyway failure is based on the shear stress across the key, neglecting surface pressure and bending, and applying a high safety factor of at least 2. The shear stress in this case is 60N/mm^2, which is not enough to cause the connection to fail, since the safety factor is more than 6.