From the balanced equation, H2SO4 + 2 KOH ---> K2SO4 + 2 H2O, we see that the molar ratio of sulfuric acid to potassium hydroxide is 1:2. Therefore:
(1 n H2SO4/2 n KOH) (0.5 n KOH/1 L KOH) (0.0167 L KOH/0.015 L H2SO4) = 0.0278 = 0.03 mol/L of H2SO4 to 1 sig fig.
Lala S.
so the concentration of the acid is 0.278 M06/10/20