The equation below shows the formation of ammonia. If 56g of nitrogen gas is used in the reaction, how much ammonia will be formed?

Question

Answer 1

According to the eq uation, you will make 2 moles of NH₃ for every mole of nitrogen gas. 56 grams of N₂ is 2 moles of gas, so you would make 4 moles of NH_3, or (4 moles)(17grams/mole)=68 grams of NH₃.