10 help me please

Question

An unknown gas at 35.1 ∘C and 1.05 atm has a molar mass of 16.04 g/mol. Assuming ideal behavior, what is the density of the gas?

Answer 1

Based on the ideal gas law: PV = nRT, in which P in atm, V in liter, n in mole, and T in Kelvin, R is the universal gas constant 0.08206 atm*L/(mol*K), one can calculate how many liters of space one mole of the gas (molar mass at 16.04 g/mol) occupies.

V = nRT/P = 1.0 mole * 0.08206 atm*L/(mol*K) *(273.15 + 35.1)K / 1.05 atm = 24.1 L

Density = mass / vol = 16.04 g / 24.1 L = 0.666 g/L