What is the specific heat of a 44 g piece of metal if 202 Joules of heat are required to raise the temperature from 22oC to 33.6oC?

Answer 1

Hello Dejanae,

Specific heat formula is q = m c ΔT

m = 44 g

q = 202 J

ΔT = T_f - T_i = 33.6 - 22.0 = 11.6 °C

c = ?

Rearrange the above equation to solve for c (specific heat),

c = q / mΔT = 202 J / (44 g x 11.6 °C) = 0.40 J/g°C (rounded to 2 significant figures)