If a container holds four gases: 0.78 atm of helium, 1.29 atm of oxygen and 0.54 atm of nitrogen, what is the pressure of the missing gas if the total pressure in the container is 4.5 atm?

Answer 1

P_total=P₁ + P₂ + P₃ +.....

So, 4.5 atm = 0.78 atm + 1.29 atm + 0.54 atm + X

X=4.5-0.78-1.29-0.54= 1.89 atm