The specific heat of mercury calculated from her data

Question

In the laboratory a student finds that it takes 17.9 Joules to increase the temperature of 10.3 grams of liquid mercury from 23.8 to 37.5 degrees Celsius.

The specific heat of mercury calculated from her data is _________ J/g°C.

Answer 1

q = mcΔT. Rearranging to solve for c gives c = q/(mΔT) = 17.9 J/[(10.3 g) (37.5^oC - 23.8^oC)] = 0.127 J/g^oC