You need a table of ΔΗf for the CH4 and CO and H2O(g). Since one isn't provided, I will use the values from my table.
ΔHf for CH4 = -74.8 kJ/mol and CO = -110.5 kJ/mol and H2O(g) = -241.82 kJ/mol
ΔHrxn = (3 H2 + CO) - (CH4 + H2O) = [ 3 (0) + (-110.5)] - [(-74.8) + (-241.82)] = + 206.12 kJ